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  • At 345 K, the half life for the decomposition of a sample of a sample of a gaseous compound initially at 55.5 kPa was 340 s. When the pressure was 27.8kPa, the half life was found to be 170 s. The

At 345 K, the half life for the decomposition of a sample of a sample of a gaseous compound initially at 55.5 kPa was 340 s. When the pressure was 27.8kPa, the half life was found to be 170 s. The order of the reactionis _________. [integer answer]

Option: 1

0


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

As we have learnt, 

The half life is related to the order of the reaction as 

\mathrm{t_{{1}/{2}}\propto[A_0]^{1-n}}

The above relation can be modified in terms of pressure as 

\mathrm{t_{{1}/{2}}\propto[P_0]^{1-n}}

\mathrm{t_{{1}/{2}}\propto \frac{1}{[P_0]^{n-1}}}

\mathrm{\frac{\left(t_{1 / 2}\right)_{1}}{\left(t_{1 / 2}\right)_{2}}=\frac{\left(P_{2})^{n-1}\right.}{\left(P_{1}\right)^{n-1}} \Rightarrow \frac{340}{170}=\left(\frac{27.8}{55.5}\right)^{n-1}}

\mathrm{\Rightarrow 2=\left(\frac{1}{2}\right)^{n-1} \Rightarrow n-1=-1 \Rightarrow n=0}

So, order of the reaction is Zero.

Hence, the correct answer is 0.

Posted by

shivangi.shekhar

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