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At a certain place the angle of dip is 30^{\circ} and the horizontal component of earth's magnetic field is 0.5 \mathrm{G}. The earth's total magnetic field (in \mathrm{G} ), at that certain place, is :
 

Option: 1

\frac{1}{\sqrt{3}}


Option: 2

\frac{1}{2}


Option: 3

\sqrt{3}


Option: 4

1


Answers (1)

best_answer

\mathrm{B_{H}=B\; \cos 30^{\circ }}

\mathrm{B=\frac{B_H}{\frac{\sqrt{3}}{2}}=\frac{1}{\sqrt{3}}G}

Hence, the correct answer is Option (1)

Posted by

SANGALDEEP SINGH

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