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Atoms of element \mathrm{X } form \mathrm{hcp} lattice and those of element \mathrm{Y} occupy \mathrm{\frac{2}{3}} of its tetrahedral Voids. The percentage of element \mathrm{X } in the lattice is _________. (Nearest integer)

Option: 1

43


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

As we have learnt,

If the number of atoms forming an HCP lattice be \mathrm{'n'}, then the number of tetratedral voids is \mathrm{2 n}.

\mathrm{\therefore\: \frac{X}{Y}=\frac{n}{\frac{2}{3} \times 2 n}=\frac{3}{4}}

\mathrm{\therefore \: \%\, \, of\, X=\frac{3}{7} \times 100\: \cong\: 43\, \%}

Hence, the answer is 43

Posted by

jitender.kumar

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