Blocks of masses m, 2m, 4m, and 8m are arranged in a line on a frictionless floor. Another block of a mass m, moving with speed v along the same line (see figure) collides with mass m in a perfectly inelastic manner. All the subsequent collisions are also perfectly inelastic. By the time the last block of a mass 8m starts moving the total energy loss is p% of the original energy. Value of 'p; is close to :
Option: 1 77
Option: 2 94
Option: 3 37
Option: 4 87
All collisions are perfectly inelastic, so after the final collision, all blocks are moving together
So let the final velocity be , so on applying momentum conservation:
Now
initial energy=
Final energy =
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