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By interchanging the digits of the number 214569837 so that odd digits are in even positions, how many 9-digit numbers can be formed?

Option: 1

2880


Option: 2

1440


Option: 3

2350

 


Option: 4

1580


Answers (1)

best_answer

The given number is 214569837.

The odd digits 1, 5, 9, 3, and 7 can be arranged in 5 even positions in 5! ways.

The even digits 2, 4, 6, and 8 can be arranged in 4 odd positions in 4! Ways.

Therefore, the total number of ways is  5!\times4!=2880  ways. 

Posted by

himanshu.meshram

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