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  • Calculate the ionisation constant of the conjugate acid of NH3. <img alt="\mathrm{Given: K_b = 1.77 \times 10^{-5}}" src="https://entrancecorner.oncodecogs.com/gif.latex?%

Calculate the ionisation constant of the conjugate acid of NH3.

\mathrm{Given: K_b = 1.77 \times 10^{-5}}

Option: 1

5.64 \times 10^{-10}


Option: 2

5.64 \times 10^{-19}


Option: 3

1.77 \times 10^{-10}


Option: 4

1.77 \times 10^{-5}


Answers (1)

best_answer

We know that, for a conjugate acid -base pair

\mathrm{k_a \times k_b = k_w}

Thus, 

\mathrm{k_a= \frac{k_w}{ k_b}= \frac{10^{-14}}{1.77 \times 10^{-5}}=5.64 \times 10^{-10}}

Therefore,option(1) is correct

Posted by

manish

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