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Calculate the pH of a solution which contains 9 mL of 1M HCl and 100 mL of 0.1 M NaOH

Option: 1

11.56


Option: 2

12.56


Option: 3

11.96


Option: 4

10.95


Answers (1)

best_answer

 

 

\mathrm{HCl}+\mathrm{NaOH} \longrightarrow \mathrm{NaCl}+\mathrm{H}_{2} \mathrm{O}

Meq. before reaction

9*1             100*0.1         0                  0

Meq. before reaction

0                      1              9                  9

\therefore\left[\mathrm{OH}^{-}\right] \text {left from } \mathrm{NaOH}=\frac{1}{109}=9.17 \times 10^{-3} M

\\\therefore \mathrm{pOH}=-\log \left[\mathrm{OH}^{-}\right] \\ \mathrm{pOH}=-\log \left[9.17 \times 10^{-3}\right] \\ \mathrm{pOH}=2.037 \\ \mathrm{pH}=11.96

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Divya Prakash Singh

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