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  • Calculate the resultant pH when 200 mL of an aqueous solution of HCl having pH = 2 is mixed 400 mL of an aqueous solution of HCl having pH = 4Option: 1</str

Calculate the resultant pH when 200 mL of an aqueous solution of HCl having pH = 2 is mixed 400 mL of an aqueous solution of HCl having pH = 4

Option: 1

3


Option: 2

2.5


Option: 3

2


Option: 4

3.33


Answers (1)

best_answer

Given pH of solution with 200 ml = 2                \therefore [HCl] = 10^{-2}

 pH of solution with 400 ml = 4                         \therefore [HCl] = 10^{-4}

 

After mixing, [HCl] = \frac{10^{-2}\times 200}{200+400}+\frac{10^{-4}\times 400}{200+400} = 3.4\times 10^{-3}

pH = -log[H+]

\Rightarrow pH = -\log(3.4\times 10^{-3}) = 2.5 

Hence, the option number (2) is correct.

Posted by

Irshad Anwar

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