The de Broglie wavelength of a tennis ball of mass 60g moving with a velocity of 10  metres per second is approximately

\left ( Planck'\! s \: constant, h= 6.63 \times 10^{-34}Js\right )

  • Option 1)

    10^{-33}metre

  • Option 2)

    10^{-31}metre

  • Option 3)

    10^{-16}metre

  • Option 4)

    10^{-25}metre

 

Answers (2)

As we learnt in 

De-broglie wavelength -

\lambda = \frac{h}{mv}= \frac{h}{p}

- wherein

where m is the mass of the particle

v its velocity 

p its momentum

\lambda = \frac{h}{m\nu }= \frac{6.63\times 10^{-34}\times 1000}{60\times 10}m

    = 11.05\times 10^{-34}m= 1.105\times 10^{-33}metres

 Correct option is option 1

 


Option 1)

10^{-33}metre

Correct Option

Option 2)

10^{-31}metre

Incorrect option

Option 3)

10^{-16}metre

Incorrect option

Option 4)

10^{-25}metre

Incorrect option

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