Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

The half -life period of a first order chemical reaction is 6.93 minutes. The time required for the completion of 99% of the chemical reaction will be \left ( \log 2= 0.301 \right )

  • Option 1)

    230.3 minutes

  • Option 2)

    23.03 minutes

  • Option 3)

    46.06 minutes

  • Option 4)

    460.6 minutes

 

Answers (1)

best_answer

As we learnt in

First Order Reaction -

The rate of the reaction is proportional to the first power of the concentration of the reaction

- wherein

Formula:

R    \rightarrow        P

a                 0

a-x             x

rate[r]=K[R]^{1}

\frac{-d(a-x)}{dt}=K(a-x)

\frac{-dx}{dt}=K(a-x)  [differentiate rate law]

ln \:[\frac{a}{a-x}]=kt \:(Integrated rate law)

Unit of k=sec^{-1}

t_\frac{1}{2}=\frac{0.693}{k}

 

 

 K=\frac{0.693}{t\frac{1}{2}}=\frac{0.693}{6.93}=\frac{1}{10}

t=\frac{2.303}{K}\:log\frac{100}{1}

t=\frac{2.303}{\frac{1}{10}}\:log10^{2}

t=46.06


Option 1)

230.3 minutes

Incorrect option

Option 2)

23.03 minutes

Incorrect option

Option 3)

46.06 minutes

Correct option

Option 4)

460.6 minutes

Incorrect option

Posted by

divya.saini

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024 Session 2: Last day to challenge answer key today
anam-khan

BTech admission 2024 without JEE; top government engineering colleges, upcoming entrance exams
anam-khan

JEE Main 2024 answer key out at jeemain.nta.ac.in; raise objections till April 14

Latest Question