Browse by Stream
Discuss Doubts
Home
Search for Exam, Articles, Questions
get app
Go To Your Study Dashboard
  1. Home
  2. Can someone explain Consider two thin identical conducting wires covered with very thin insulating material. One of the wires is bent into a loop and produces magnetic field B1' at its centre when a current I passes through it. The second wire is
# Engineering

Consider two thin identical conducting wires covered with very thin insulating  material. One of the wires is bent into a loop and produces magnetic field B1'  at its centre when a current I passes through it.  The second wire is bent into a coil with  three identical loops adjacent to each other and produces magnetic field B2 at the centre of the loops when current I/3 passes through it. The ratio B1 : B2 is :  

 

  • Option 1)

    1:1

  • Option 2)

    1:3

  • Option 3)

    1:9

  • Option 4)

    9:1

 

Answers (1)
S Sabhrant Ambastha

As we discussed in concept

Magnetic field due to cCrcular Current Carrying arc -

B=\frac{\mu_{o}}{4\pi}\:\frac{2\pi i}{r}=\frac{\mu_{o}i}{2r}

- wherein

 

 and concept

Magnetic Field at the axis due to circular current carrying wire -

B_{axis}=\frac{\mu_{0}}{4\pi }.\frac{2\pi Nir^{2}}{(x^{2}+r^{2})\frac{3}{2}}

- wherein

N is numbers of turn in coil

 

 For loop  B=\frac{\mu _{0}nI}{2a} where a is the radius of the loop.

B_{1}=\frac{\mu _{0}I}{2a}

For co.l        B=\frac{\mu _{0}I}{4\pi}\frac{2nA}{x^{3}}          at the centre x=radius of loop

B_{2}=\frac{\mu _{0}}{4\pi}\frac{2\times 3\times\left ( \frac{5}{3} \right )\times \pi\left ( \frac{a}{3} \right )^{3}}{a^{3}}= \frac{\mu _{0}.33}{2a}

\frac{B_{1}}{B_{2}}= \frac{\frac{\mu_{0} I}{2a}}{\frac{\mu _{0}.3I}{2a}}=\frac{B_{1}}{B_{2}}= 113

 


Option 1)

1:1

Incorrect Option

Option 2)

1:3

Correct Option

Option 3)

1:9

Incorrect Option

Option 4)

9:1

Incorrect Option

Similar Questions

Preparation Products

JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Knockout JEE Main April 2021 (Subscription)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 4999/-
Buy Now
Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Knockout JEE Main January 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Exams
Articles
Questions