If in a circular coil A of radius R, current I is flowing and in another coil B of radius 2R a current 2I is flowing, then the ratio of the magnetic fields, B_{A} and B_{B} , produced by them will be

  • Option 1)

    1

  • Option 2)

    2

  • Option 3)

    1/2

  • Option 4)

    4

 

Answers (1)

As we learnt in concept

Magnetic Field due to circular coil at Centre -

B_{Centre}=\frac{\mu_{0}}{4\pi }\frac{2\pi Ni}{r}=\frac{\mu_{0} Ni}{2r}

 

 

\therefore \; \; \frac{B_{A}}{B_{B}}=\frac{I_{A}}{I_{B}}\times \frac{R_{B}}{R_{A}}=\left ( \frac{1}{2} \right )\left ( \frac{2}{1} \right )=1


Option 1)

1

Correct option

Option 2)

2

Incorrect option

Option 3)

1/2

Incorrect option

Option 4)

4

Incorrect option

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