Two coaxial solenoids of different radii carry current I in the same direction. Let \underset{F_{1} }{\rightarrow}  be the magnetic force on the inner solenoid due to the outer one and \underset{F_{2} }{\rightarrow}  be the magnetic force on the outer solenoid due to the inner one. Then :

 

  • Option 1)

    \underset{F_{1} }{\rightarrow}   =    \underset{F_{2} }{\rightarrow}   =  0

  • Option 2)

    \underset{F_{1} }{\rightarrow}  is radially inwards and   \underset{F_{2} }{\rightarrow} radially outwards

  • Option 3)

    \underset{F_{1} }{\rightarrow}is radially inwards and  \underset{F_{2} }{\rightarrow} = 0

  • Option 4)

    \underset{F_{1} }{\rightarrow}is radially  outwards  \underset{F_{2} }{\rightarrow} =  0

 

Answers (1)

As we learnt in 

Solenoid -

A cylinderical coil of many tightly wound turns of insulated wire generally diameter of the coil smaller than its length 

- wherein

 

 \overrightarrow{F_{1}}= \overrightarrow{F_{2}}=0


Option 1)

\underset{F_{1} }{\rightarrow}   =    \underset{F_{2} }{\rightarrow}   =  0

Correct Option

Option 2)

\underset{F_{1} }{\rightarrow}  is radially inwards and   \underset{F_{2} }{\rightarrow} radially outwards

Incorrect Option

 

Option 3)

\underset{F_{1} }{\rightarrow}is radially inwards and  \underset{F_{2} }{\rightarrow} = 0

Incorrect Option

 

Option 4)

\underset{F_{1} }{\rightarrow}is radially  outwards  \underset{F_{2} }{\rightarrow} =  0

Incorrect Option

 

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