Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Can someone explain One end of a massless rope, which passes over a massless and frictionless pulley P is tied to a hook C While the other end is free. Maximum tension that the rope can bear is 960 N.With what value of maximum safe acceleration (in m

One end of a massless  rope, which passes over a massless and frictionless pulley P is tied to a hook  C While  the other end is free. Maximum tension that  the rope can bear is 960 N.With what value of  maximum safe acceleration (in ms-2) can a man of 60 kg climb on the rope?

  • Option 1)

    16

  • Option 2)

    6

  • Option 3)

    4

  • Option 4)

    8

 

Answers (1)

best_answer

As we learnt in

Motion of connected blocks over pulley -

Equation of motion for   m_{1}

F_{net}=T-m_{1}g=m_{1}a

Equation of Motion for   m_{2}

F_{net}=m_{2}g-T=m_{2}a

 

- wherein

a=\frac{[m_{2}-m_{1}\:]g}{m_{1}+m_{2}}

T=\frac{2m_{1}m_{2}\:g}{m_{1}+m_{2}}


 

 

 

 

:    T - 60g = 60 a

  or    960 - (60\times10) = 60a 

or    60a = 360

or    a = 6ms-2

Correct option is 2.


Option 1)

16

This is an incorrect option.

Option 2)

6

This is the correct option.

Option 3)

4

This is an incorrect option.

Option 4)

8

This is an incorrect option.

Posted by

Aadil

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JoSAA 2024 round 4 seat allotment results out at josaa.nic.in; report online by July 15

Latest Question