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  • Can someone explain - Oscillations and Waves - JEE Main-6

y = 5\cos\frac{\pi x}{25}\sin 100\pi t. A node will not occur at distance x is equal to in a stationary wave

  • Option 1)

    25 cm

  • Option 2)

    62.5 cm

  • Option 3)

    12.5 cm

  • Option 4)

    37.5 cm

 

Answers (1)

best_answer

node will occur , where 

\frac{\pi X}{25}=\frac{\pi }{2},\frac{3\pi }{2},\frac{5\pi }{2} etc.

 X= 12.5, 37.5, 62.5 etc

 

Node in standing wave -

The position at which amplitude of oscillation has zero value are called nodes.

- wherein

At nodes

\sin kx= 0\\

kx= 0,\pi ,2\pi ........n\pi

 

 


Option 1)

25 cm

This is correct

Option 2)

62.5 cm

This is incorrect

Option 3)

12.5 cm

This is incorrect

Option 4)

37.5 cm

This is incorrect

Posted by

Avinash

View full answer

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