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  • Can someone explain - Redox Reaction and Electrochemistry - JEE Main

Which of the following chemical reactions depicts the oxidising behaviour  of H_{2}SO_{4} ?

  • Option 1)

    2HI+H_{2}SO_{4}\rightarrow I_{2}+SO_{2}+2H_{2}O

     

     

     

  • Option 2)

    Ca\left ( OH \right )_{2}+H_{2}SO_{4}\rightarrow CaSO_{4}+2H_{2}O

  • Option 3)

    NaCl+H_{2}SO_{4}\rightarrow NaHSO_{4}+HCl

  • Option 4)

    2PCl_{5}+H_{2}SO_{4}\rightarrow2POCl_{3}+2HCl+SO_{2}Cl_{2}

 

Answers (1)

As we learnt in

Oxidation Number -

Oxidation number denotes the oxidation state of an element in a compound ascertained according to a set of rules formulated on the basis that electron pair in a covalent bond belogs entirely to more electronegative elements.

-

 

 and

Oxidising Agent -

A substance that act as acceptor of electron is called oxidising agent. Cl2 itself get reduced in the process

- wherein

e.g. 2Na(s) + Cl_{2}(g)\rightarrow 2Na^{+}Cl^{-}

Cl2  act as oxidising agent

 

  

In the reaction,

In this reaction oxidation number of I increases by one, thus this is an oxidation reaction and HI behaves as a reducing agent.

In this reaction oxidation number of S decreases by two, thus this is a reduction reaction and H2SO4   behaves as oxidising agent.


Option 1)

2HI+H_{2}SO_{4}\rightarrow I_{2}+SO_{2}+2H_{2}O

 

 

 

This option is correct.

Option 2)

Ca\left ( OH \right )_{2}+H_{2}SO_{4}\rightarrow CaSO_{4}+2H_{2}O

This option is incorrect.

Option 3)

NaCl+H_{2}SO_{4}\rightarrow NaHSO_{4}+HCl

This option is incorrect.

Option 4)

2PCl_{5}+H_{2}SO_{4}\rightarrow2POCl_{3}+2HCl+SO_{2}Cl_{2}

This option is incorrect.

Posted by

Vakul

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