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  • Can someone explain - Statistics and Probability - JEE Main

A die is thrown. Let A be the event that the number obtained is greater than 3. Let B be the event that the number obtained is less than 5. Then P(A\cup B) is

  • Option 1)

    \frac{2}{5}

  • Option 2)

    \frac{3}{5}

  • Option 3)

    0

  • Option 4)

    1

 

Answers (1)

best_answer

As we learnt in

Algebra of events -

[A\cup B\rightarrow at least one event.

A\cap B\rightarrow both occur simultaneous.

A\cap \overline{B}= A-B, occurrence of event A but not B.

\overline{A}\cap \overline{B}\rightarrow neither A or B.]

- wherein

where A & B are any two events.

 

 

 

Set A = \left \{ 4, 5, 6 \right \}

Set B = \left \{ 1, 2, 3, 4 \right \}

Set A\cup B = \left \{ 1, 2,3, 4, 5, 6 \right \}

Which is set of all possible outcomes. Hence

P\left ( A\cup B \right ) = 1


Option 1)

\frac{2}{5}

Incorrect

Option 2)

\frac{3}{5}

Incorrect

Option 3)

0

Incorrect

Option 4)

1

Correct

Posted by

divya.saini

View full answer

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