The lanthanide ion that would show colour is :

  • Option 1)

    Lu^{3+}

  • Option 2)

    Gd^{3+}

  • Option 3)

    La^{3+}

     

  • Option 4)

    Sm^{3+}

 

Answers (1)

Fully filled f-orbitals

\downarrow

Lu^{3+}=[xe]4F^{14}\; \; \; Gd^{3+}=[xe]4F^{7}=Half-filled\; f-orbitals

La^{3+}=[xe]4F^{0}\; \; \; Sm^{3+}=[xe]4F^{5}=5 \; unpaired\; \; e^{-}

                      \\\downarrow\\N\! o\; electrons

\therefore \; Sm^{3+} ion shows colour

 


Option 1)

Lu^{3+}

Option 2)

Gd^{3+}

Option 3)

La^{3+}

 

Option 4)

Sm^{3+}

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