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  • Can someone explain The reaction of propene with HOCl (Cl2+H2O) proceeds through the intermediate :

The reaction of propene with HOCl (Cl2+H2O) proceeds through the intermediate :

  • Option 1)

    CH3−CH+−CH2−OH

  • Option 2)

    CH3−CH+−CH2−Cl

  • Option 3)

    CH_{3}-CH(OH)-CH_{2}^{+}\textrm{}

  • Option 4)

    CH_{3}-CHCI-CH_{2}^{+}\textrm{}

 

Answers (1)

As we learnt in 

Addition of HBr in presence of peroxide -

In presence of peroxide follow anti markovnikov rule.

- wherein

CH_3-CH=CH_2 + HBr \rightarrow CH_3-CH_2-CH_2-Br

 

 Addition reaction to an alkene proceeds according to Markovnikov's Rule  to give the most stalite intermediate.CH_{3}CH= CH_{2}+HOCl \overset{Cl_{2},H_{2}o}{\rightarrow}CH_{3}-\overset{+}{CH}-CH_{2}Cl\ (most\ stable\ intermediate) +OH^{-}


Option 1)

CH3−CH+−CH2−OH

Incorrect Option

Option 2)

CH3−CH+−CH2−Cl

Correct Option

Option 3)

CH_{3}-CH(OH)-CH_{2}^{+}\textrm{}

Incorrect Option

Option 4)

CH_{3}-CHCI-CH_{2}^{+}\textrm{}

Incorrect Option

Posted by

Vakul

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