Group V cations are precipitated in form of carbonates \left ( NH_{4} \right )_{2}.CO_{3}  why can we not use Na_{2} CO_{3} instead of \left ( NH_{4} \right )_{2}CO_{3}

  • Option 1)

    Because Na_{2}CO_{3} will precipitate MgCO_{3}

  • Option 2)

    Because Na_{2}CO_{3} in insoluble in water

  • Option 3)

    Because it is an ionic compound

  • Option 4)

    None of these

 

Answers (1)
A Aadil Khan

As we discussed in concept

Test of Carbonate ion -

Add BaCl_2  Solution which give white precipitate

Ba^{2+} + CO^{2-}_3 \rightarrow BaCO_3 \: (white)

- wherein

White ppt confirm the CO^{2-}_3 ions

 

 Na_{2}CO_{3} is highly ionised electrolyte, producing very high concentration of carbonic ions. Thus, precipitating MgCO_{3}

 


Option 1)

Because Na_{2}CO_{3} will precipitate MgCO_{3}

This option is correct.

Option 2)

Because Na_{2}CO_{3} in insoluble in water

This option is incorrect.

Option 3)

Because it is an ionic compound

This option is incorrect.

Option 4)

None of these

This option is incorrect.

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