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Can someone explain - Trigonometry - JEE Main-2

If \cos ^2 \theta = 1  then Find such \theta that satisfy all values 

  • Option 1)

    2n\pi

  • Option 2)

    (2n+1)\pi

  • Option 3)

    n \pi

  • Option 4)

    (2n\pm 1)\pi

 
Answers (1)
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As we have learned

Results from General Solution -

\cos \Theta = -1 \Rightarrow \Theta = \left ( 2n+1 \right )\pi

-

 

 \cos^2 \theta = 1 \; \; \; \cos \theta = 1 \; \; or \cos \theta = -1

\theta = 2n \pi \; \; \; or \theta = (2n+1)\pi

Thus \theta = both odd and even multiplies of \pi

\theta = n \pi

 


Option 1)

2n\pi

Option 2)

(2n+1)\pi

Option 3)

n \pi

Option 4)

(2n\pm 1)\pi

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