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  • Can someone explain When the string of a sonometer of length L between the bridges vibrates in the 2nd overtone, the amplitude of vibration is max at

When the string of a sonometer of length L between the bridges vibrates in the 2nd overtone, the amplitude of vibration is max at 

  • Option 1)

    \left ( \frac{L}{2} \right )

  • Option 2)

    \left ( \frac{L}{4}, \frac{3L}{4}\right )

  • Option 3)

    \left ( \frac{L}{6}, \frac{3L}{6}\right )

  • Option 4)

    \left ( \frac{L}{8}, \frac{3L}{8}\right )

 

Answers (1)

best_answer

\frac{3\Lambda }{2}= L \Rightarrow \Lambda = \frac{2L}{3}

Amplitude will be \frac{L}{6}, \frac{3L}{6} , \frac{5L}{6} etc. 

 

Sonometer -

It is a device  used to measure velocity of transverse mechanical wave in a stretched wire.

- wherein

The principle of sonometer is based on resonance of string vibration.

 

 


Option 1)

\left ( \frac{L}{2} \right )

This is incorrect

Option 2)

\left ( \frac{L}{4}, \frac{3L}{4}\right )

This is incorrect

Option 3)

\left ( \frac{L}{6}, \frac{3L}{6}\right )

This is correct

Option 4)

\left ( \frac{L}{8}, \frac{3L}{8}\right )

This is incorrect

Posted by

Avinash

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