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  • Can someone help me with this, A sound absorber attenuates the sound level by 20dB. The intensity decreases by a factor of

A sound absorber attenuates the sound level by 20dB. The intensity decreases by a factor of

  • Option 1)

    1000

  • Option 2)

    10000

  • Option 3)

    10

  • Option 4)

    100

 

Answers (1)

B_{1} = 10 log \left [ \frac{I}{I_{o}} \right ] ; B_{2} = 10 log \left [ \frac{I'}{I_{o}} \right ]

Given B2 - B1 = 20

20 = 10 log \left [ \frac{I'}{I} \right ] \Rightarrow I' = 100 I

 

Sound level in decibels -

\beta = \: \: 10 \log_{10}\left ( I/I_{0} \right ),\\for \: \: I=I_{0}\\ \beta =0

- wherein

Where I is the intensity of the sound and I_{0}  is a constant reference intensity = 10-12 W/m2

 

 

 


Option 1)

1000

This is incorrect.

Option 2)

10000

This is incorrect.

Option 3)

10

This is incorrect.

Option 4)

100

This is correct.

Posted by

subam

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