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Can someone help me with this, - Current Electricity - JEE Main-4

In the given circuit , an ideal voltmeter connected across the 10\Omega

resistance reads 2V. The internal resistance r , of each cell is :

 

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

 
Answers (1)
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S solutionqc

 

In series Grouping -

R_{eq}=R_{1}+R_{2}+R_{3}+\cdot \cdot \cdot +R_{n}

- wherein

R_{eq}- Equivalent Resistance

 

 

In parallel Grouping -

\frac{1}{R_{eq}}=\frac{1}{R_{1}}+\frac{1}{R_{2}}+\cdot \cdot \cdot +\frac{1}{R_{n}}

-

 

 

So,

V = 6 x i = 2

i=\frac{1}{3}A

i=\frac{2E}{2r+2+6}

   =\frac{2\times 1.5}{2r+8}

  =\frac{1}{3}

=>9=2r+8

=> r=0.5\Omega


Option 1)

Option 2)

Option 3)

Option 4)

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