Even Carnot engine cannot give 100% efficiency because we cannot

  • Option 1)

    prevent radiation

  • Option 2)

    find ideal sources

  • Option 3)

    reach absolute zero temperature

  • Option 4)

    eliminate friction.

 

Answers (1)

As we learnt in 

Efficiency of a carnot cycle -

\eta =\frac{W}{Q_{1}-Q_{2}}=1-\frac{T_{2}}{T_{1}}

T_{1}\, and\, T_{2}  are in kelvin
 

- wherein

T_{1}= Source temperature

T_{2}= Sink Temperature

\left ( T_{1} > T_{2}\right )

 

  For Carnot Cycle

Efficiency \eta =1-\frac{T2}{T2}

Efficiency will be 100% only if T = O K

But this not possible.


Option 1)

prevent radiation

This option is incorrect.

Option 2)

find ideal sources

This option is incorrect.

Option 3)

reach absolute zero temperature

This option is correct.

Option 4)

eliminate friction.

This option is incorrect.

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