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For a reaction scheme if the rate of formation of B is set to be zero then the concentration of B is given by:
Option 1)
$\left ( k_{1}-k_{2} \right )\left [A \right ]$
Option 2)
$k_{1}k_{2} \left [A \right ]$
Option 3)
$\left ( k_{1}+k_{2} \right )\left [A \right ]$
Option 4)
$\left ( \frac{k_{1}}{k_{2}} \right )\left [A \right ]$

Answers (1)

best_answer

$\frac{d[B]}{dt}=0$ (given) [B]=?

$R_{1}=k_{1}\left [ A \right ]$ $R_{2}=k_{2}\left [ B \right ]$

net rate of formation of $B=\frac{d[B]}{dt}=R_{1}-R_{2}$

$k_{1}[A]-k_{2}[B]=0$

$k_{1}[A]=k_{2}[B]$

$[B]=\left ( \frac{k_{1}}{k_{2}} \right )[A]$

Option 1)

$\left ( k_{1}-k_{2} \right )\left [A \right ]$

Option 2)

$k_{1}k_{2} \left [A \right ]$

Option 3)

$\left ( k_{1}+k_{2} \right )\left [A \right ]$

Option 4)
$\left ( \frac{k_{1}}{k_{2}} \right )\left [A \right ]$

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