For a reaction scheme if the rate of formation of B is set to be zero then the concentration of B is given by:

  • Option 1)

    \left ( k_{1}-k_{2} \right )\left [A \right ]

  • Option 2)

    k_{1}k_{2} \left [A \right ]

  • Option 3)

    \left ( k_{1}+k_{2} \right )\left [A \right ]

  • Option 4)

    \left ( \frac{k_{1}}{k_{2}} \right )\left [A \right ]

Answers (1)

\frac{d[B]}{dt}=0   (given) [B]=?

R_{1}=k_{1}\left [ A \right ]             R_{2}=k_{2}\left [ B \right ]

net rate of formation of B=\frac{d[B]}{dt}=R_{1}-R_{2}

k_{1}[A]-k_{2}[B]=0

k_{1}[A]=k_{2}[B]

[B]=\left ( \frac{k_{1}}{k_{2}} \right )[A]


Option 1)

\left ( k_{1}-k_{2} \right )\left [A \right ]

Option 2)

k_{1}k_{2} \left [A \right ]

Option 3)

\left ( k_{1}+k_{2} \right )\left [A \right ]

Option 4)

\left ( \frac{k_{1}}{k_{2}} \right )\left [A \right ]

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