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If 50 calorie are added to a system and system does work of 30 calorie on surroundings, the change in internal energy of system is:

  • Option 1)

    20 cal.

  • Option 2)

    50 cal.

  • Option 3)

    40 cal.

  • Option 4)

    30 cal.

 

Answers (1)

best_answer

As learnt in

IUPAC Sign Convention -

Any type of energy (Heat, Work ) given to system is positive 

Any type of energy take out from the system

 

- wherein

W= +10 j i.e. 10 J work done on the system

q= -10 j i.e. 10 J released by the system

 

 

First law of Thermodynamics -

Energy of universe is always conserved or total energy of an isolated system is always conserved

\Delta E= q + W


 

- wherein

\Delta E= Internal Energy

q= Heat

W= work

 

 \Delta E= g -w (work is done by the system, so w= -ve)

          = 50 -30

          = 20 cal

 

 


Option 1)

20 cal.

correct

Option 2)

50 cal.

Incorrect

Option 3)

40 cal.

Incorrect

Option 4)

30 cal.

Incorrect

Posted by

Plabita

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