Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Can someone help me with this, If a certain amount of slaked lime (Ca(OH)2) on heating gave 33.6 L of H2O vapour at STP, then what is the number of moles of slaked lime we had?

If a certain amount of slaked lime (Ca(OH)2) on heating gave 33.6 L of H2O vapour at STP, then what is the number of moles of slaked lime we had?

 

  • Option 1)

    1.5

  • Option 2)

    1

  • Option 3)

    2

  • Option 4)

    2.5

 

Answers (1)

As we learnt in

Number of Moles of a gas at STP -

no of moles of a gas at STP= given volume of gas / 22.4 liter

-

 

 Ca(OH)_{2}\rightarrow CaO+H_{2}O

\therefore \: 1 \: mole\: o\! f Ca(OH)_{2}\: Gives\: 1 \: mole\: of\: H_{2}O

\therefore \: 1.5 \: mole\: o\! f Ca(OH)_{2}\: Gives\: 1.5 \: mole\: of\: H_{2}O

 

Moles of H2O =\frac{33.6}{22.4}= 1.5

 


Option 1)

1.5

Correct

Option 2)

1

Incorrect

Option 3)

2

Incorrect

Option 4)

2.5

Incorrect

Posted by

Vakul

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main Result 2024 Live: JEE April results at jeemain.nta.ac.in likely today; cutoff, rank predictor, update
anam-khan

JEE Main 2024 session 2 final answer key out at jeemain.nta.ac.in; steps to check probable scores
anam-khan

JEE Main Result 2024 Live: Download session 2 final answer key at jeemain.nta.ac.in; rank predictor, cutoff

Latest Question