Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Can someone help me with this, If in the circuit, power dissipation is 150 W, then R is

If in the circuit, power dissipation is 150 W, then R is

  • Option 1)

    2\Omega \;

  • Option 2)

    \; 6\Omega\;

  • Option 3)

    \; \; 5\Omega\;

  • Option 4)

    \; 4\Omega

 

Answers (2)

As we learnt in 

if R=r -

P_{max}=\frac{E^{2}}{4r}

- wherein

Power delivered will be maximum

 

 and

 

Parallel Grouping -

Potential - Same

Current - Different

- wherein

 

The equivalent resistance is Re_{2}= \frac{2\times R}{2+R}

Power dissipation P= \frac{v^{2}}{R}

150 = \frac{15\times 15}{Re_{2}}

= Re_{2} = \frac{15}{10}= \frac{3}{2}

\frac{2R}{2+R} = \frac{3}{2}

\Rightarrow 4R = 6+3R

R = 6\Omega

 

 

 

 

 


Option 1)

2\Omega \;

This option is incorrect.

Option 2)

\; 6\Omega\;

This option is correct.

Option 3)

\; \; 5\Omega\;

This option is incorrect.

Option 4)

\; 4\Omega

This option is incorrect.

Posted by

Sabhrant Ambastha

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024 Topper: Farmer’s son Gajare Nilkrishna says ‘keep questioning until you understand’
anam-khan

NIT Puducherry Cut-off 2024: Computer Science and Engineering had highest closing rank last year
anam-khan

JEE Mains: Farmer's son from remote Maharashtra village aces exam

Latest Question