In the circuit below, identify the equivalent gate

 

  • Option 1)

    OR

  • Option 2)

    AND

  • Option 3)

    NOR

  • Option 4)

    NAND

 

Answers (1)

 

OR gate -

Relation between input and output

    Y= A+B

- wherein

A and B are input

Y is out put

 

 

D'morgan's Theorem -

1)     \overline{A+B }= \bar{A}\cdot \bar{B}

2)      \overline{A\cdot B }= \bar{A}+ \bar{B}

3)    \overline{\bar A+ \bar B }= {A}\cdot {B}

4)    \overline{\bar A\cdot \bar B }= {A}+{B}

- wherein

A and B are input.

 Y=\overline{\bar{A}.\bar{B}}= \bar{\bar{A}}+\bar{\bar{B}}   (D'morgabs law)

=A+B

This represent or gate

 


Option 1)

OR

Option is correct

Option 2)

AND

Option is incorrect

Option 3)

NOR

Option is incorrect

Option 4)

NAND

Option is incorrect

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