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  • Can someone help me with this, - Magnetic Effects of Current and Magnetism - JEE Main-3

The dipole moment of a circular loop carrying a current I, is m and the magnetic field at the centre of the loop is B1. When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is B2. The ratio \frac{B1}{B2} is:

  • Option 1)

    \frac{1}{\sqrt{2}}

  • Option 2)

    2

  • Option 3)

    \sqrt{3}

  • Option 4)

    \sqrt{2}

 

Answers (2)

best_answer

As we learnt that

 

Magnetic moment (M) -

M=NiA

- wherein

N-number of turns in the coil 

i-current throughout the coil 

A-area of the coil 

 

 Dipole \: moment (m)=I.\pi R^{2}

B=\frac{\mu _{o}I}{2R}\; \; \: \: \: \: \: \: eq 1

\because R\propto \sqrt{m}\: (keeping\: I\: constant)

\therefore B\propto \frac{1}{\sqrt{m}}

\therefore \frac{B1}{B2}=\sqrt{\frac{m2}{m1}}=\sqrt{2}


Option 1)

\frac{1}{\sqrt{2}}

This is incorrect

Option 2)

2

This is incorrect

Option 3)

\sqrt{3}

This is incorrect

Option 4)

\sqrt{2}

This is correct

Posted by

divya.saini

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