A solid body of constant heat capacity 1 J/0C is being heated by keeping it in contact with reservoirs in two ways : 

  (i)    Sequentially keeping in contact with 2 reservoirs such that each reservoir      
          supplies same amount of heat.       
  (ii)    Sequentially keeping in contact with 8 reservoirs such that each reservoir       
          supplies same amount of heat.          
          In both the cases body is brought from initial  temperature  1000C  to  final   
         temperature 2000C. Entropy change of the body in the two cases respectively is :                    

 

  • Option 1)

    ln2,4ln2

  • Option 2)

    ln2,ln2

  • Option 3)

    ln2,2ln2

  • Option 4)

    2ln2,8ln2

 

Answers (1)

As we learnt in

Solids -

It is the type of matter which has got fixed shape and volume .The force of attraction between any two molecules of a solid is very large .

- wherein

e.g.Nacl,Diamond,Graphite

 

 \Delta S=\int\frac{msdt}{T}=ms\ln \left(\frac{T_{f}}{T_{i}} \right )

\Delta S=1.\ln \left(\frac{T_{f}}{T_{i}} \right )

\Delta S is state depedent. Its value changes by changing state hence if remain same in two processes.

\Delta S=ln2 for both bu temperature should be in Kelvin. 

Correct option is 2.


Option 1)

ln2,4ln2

This is an incorrect option.

Option 2)

ln2,ln2

This is the correct option.

Option 3)

ln2,2ln2

This is an incorrect option.

Option 4)

2ln2,8ln2

This is an incorrect option.

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