Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Can someone help me with this, - Oscillations and Waves - JEE Main-5

The equation of a transverse wave is given by y = 10\sin\pi(0.01x -2t), where x and y are in cm and t is second. Its frequency is

  • Option 1)

    10 sec-1

  • Option 2)

    2  sec-1

  • Option 3)

    1 sec-1

  • Option 4)

    0.01 sec-1

 

Answers (1)

best_answer

Comparing with the standard equation -

y = 10 sin \frac{2\pi }{\lambda } (vt - x) we have v = 200cm / sec , \lambda = 200 cm

 n = \frac{v}{\lambda} = 1 sec^{-1}

 

Pulse -

When we flick one end of a long string that is under tension and has its opposite end fixed .In this manner, a single bump is formed and travel along the string this bump is called pulse.

- wherein

Pulse has a defined height and defined speed of propagation along the medium . The shape of the pulse changes very little.

 

 


Option 1)

10 sec-1

This is incorrect.

Option 2)

2  sec-1

This is incorrect.

Option 3)

1 sec-1

This is correct.

Option 4)

0.01 sec-1

This is incorrect.

Posted by

prateek

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main Result 2024 Live: JEE Mains session 2 results at jeemain.nta.ac.in soon; rank predictor
anam-khan

JEE Main 2024 session 2 final answer key out at jeemain.nta.ac.in; steps to check probable scores
anam-khan

JEE Main Result 2024 Live: Download session 2 final answer key at jeemain.nta.ac.in; rank predictor, cutoff

Latest Question