A steel wire having a radius of 2.0 mm, carrying a load of 4 kg, is hanging from a ceiling. Given that g=3.1\; \pi ms^{-2}, what will be the tensile stress that would be developed in the wire ?

  • Option 1)

    4.8\times10^{6}Nm^{-2}

  • Option 2)

    5.2\times10^{6}Nm^{-2}
     

  • Option 3)

    3.1\times10^{6}Nm^{-2}

     

  • Option 4)

    6.2\times10^{6}Nm^{-2}

 

Answers (1)

r=2mm

m=4kg, g=3.1\pi \; ms^{-2}

So, F = mg

Stress = \frac{F}{A}=\frac{mg}{\pi r^{2}}=\frac{m\pi \times3.1}{\pi (4)\times10^{-6}}

Stress = \frac{4\times3.1\times\pi }{\pi \times10^{-6}\times4}=3.1\times10^{6}N/m^{2}

 


Option 1)

4.8\times10^{6}Nm^{-2}

Option 2)

5.2\times10^{6}Nm^{-2}
 

Option 3)

3.1\times10^{6}Nm^{-2}

 

Option 4)

6.2\times10^{6}Nm^{-2}

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