Water from a pipe is coming at a rate of 100 liters per minute. If the radius of the pipe is 5 cm, the Reynolds number for the flow is of the order of : (density\; of \: water=1000 kg/m^{3}, coefficient\; of \: viscosity\: of\: water = 1mPa\; s)
 

  • Option 1)

    10^{6}

  • Option 2)

    10^{2}

  • Option 3)

    10^{3}

     

  • Option 4)

    10^{4}

Answers (1)

\rho _{w}=10^{3}kg/m^{3}

\eta =1\; mPa\; s

r=5\; cm

Rate of volume flow = A.V=\pi r^{2}.V=10^{2}\frac{lit}{min}

\Rightarrow \pi r^{2}.V=\frac{10^{2}\times10^{-3}}{60}=\frac{1}{600}\; m^{3}/s

V=(\frac{1}{600}\times \frac{1}{\pi \times25\times10^{-4}})

Re = Reynolds number =\frac{\rho .V.D}{\eta }

R_e=\frac{10^{3}\times(\frac{1}{600}\times\pi \times25\times10^{-4})\times(2\times5\times10^{-2})}{10^{-3}}

Re\approx 10^{4}


Option 1)

10^{6}

Option 2)

10^{2}

Option 3)

10^{3}

 

Option 4)

10^{4}

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