The diameter of zinc atom is 2.6 Å. The total number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side length-wise are

  • Option 1)

    6.15\times10^{9}

  • Option 2)

    2.6\times10^{9}

  • Option 3)

    2.6\times10^{8}

  • Option 4)

    6.15\times10^{7}

 

Answers (1)

As we discussed in concept

Atomic Radius -

The distance from the centre of the nucleus to the outermost shell containing the electrons is called atomic radius.It can be measured by the spectroscopic method and by x-ray diffraction or electron diffraction techniques.

-

 

 Diameter = 2.6\times10^{-10}m

Length = 1.6\times10^{-2}m

No. of zinc atoms = \frac{1.6\times 10^{-2}}{2.6\times 10^{-10}}\:=\:6.15\times 10^{7}


Option 1)

6.15\times10^{9}

This option is incorrect.

Option 2)

2.6\times10^{9}

This option is incorrect.

Option 3)

2.6\times10^{8}

This option is incorrect.

Option 4)

6.15\times10^{7}

This option is correct.

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