Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Can someone help me with this, The normal to the curve, x2 + 2xy - 3y2 = 0, at (1,1) :

The normal to the curve, x2 + 2xy - 3y2 = 0, at (1,1) :

  • Option 1)

    does not meet the curve again.

  • Option 2)

    meets the curve again in the second quadrant.

  • Option 3)

    meets the curve again in the third quadrant.

  • Option 4)

    meets the curve again in the fourth quadrant.

 

Answers (1)

As we learnt in 

Equation of Normal -

Equation of normal to the curve  y = f(x) at the point  P(x1, y1) on the curve having a slope  MN  is 

(y-y_{1})=M_{N}(x-x_{1})


=\frac{-1}{\frac{dy}{dx}_{(x_{1},y_{1})}}(x-x_{1})

-

 

 Move to Tangent Normal

2x+2.1y+2x\frac{dy}{dx}-6y\frac{dy}{dx}=0

2+2+2\frac{dy}{dx}-6\frac{dy}{dx}=0

4-4\frac{dy}{dx}=0

\therefore \frac{dy}{dx}=1

m_{N}=-1

\therefore y-1=-1(x-1)=-x+1

\therefore x+y=2 solve from x & y

\therefore x=3, y=-1

 


Option 1)

does not meet the curve again.

This option is incorrect

Option 2)

meets the curve again in the second quadrant.

This option is incorrect

Option 3)

meets the curve again in the third quadrant.

This option is incorrect

Option 4)

meets the curve again in the fourth quadrant.

This option is correct

Posted by

Sabhrant Ambastha

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main Maths 2025: Five tips to score high marks in ‘toughest’ subject; most important chapters
anam-khan

JEE Main 2025 exam city intimation slip for session 1 soon at jeemain.nta.nic.in
anam-khan

Focus on modern physics, formulas to solve tricky problems; 5 tips to tackle JEE Main physics 2025

Latest Question