The percentage composition of carbon by mole in methane is:

  • Option 1)

    75%

  • Option 2)

    80%

  • Option 3)

    25%

  • Option 4)

    20%

Answers (1)

mole % of 'C' in CH=   \frac{mole\;of\;C}{mole \; of\; C + mole\; of\; hydrogen}\times 100

                                  = \frac{nc}{n_{H}+n_{c}}\times 100

For 1 mole of C, there are 4 moles of hydrogen

\therefore n_{c}=1 and n_{H}=4

=\frac{1}{1+5}\times 100=20%


Option 1)

75%

Option 2)

80%

Option 3)

25%

Option 4)

20%

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