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  • Can someone help me with this, Three charges are placed at the vertices of an equilateral triangle of side ‘a’ as shown in the following figure. The force experienced by the charge placed at the vertex A in a direction normal to BC is

Three charges are placed at the vertices of an equilateral triangle of side ‘a’ as shown in the following figure. The force experienced by the charge placed at the vertex A in a direction normal to BC is

  • Option 1)

    \frac{Q^{2}}{(4\pi \varepsilon _{0}a^{2})}\;

  • Option 2)

    \; \; \frac{-Q^{2}}{(4\pi \varepsilon _{0}a^{2})}\;

  • Option 3)

    \; Zero\;

  • Option 4)

    \; \frac{Q^{2}}{(2\pi \varepsilon _{0}a^{2})}

 

Answers (1)

best_answer

As we learned

Magnitude of the Resultant force -

F_{net}=\sqrt{F_{1}^{2}+F_{2}^{2}+2F_{1}F_{2}\cos \Theta }

- wherein

 

 \left | \underset{F_{B}}{\rightarrow} \right |=\left | \underset{F_{C}}{\rightarrow} \right |=k.\frac{Q^{2}}{a^{2}}

Hence force experienced by the charge at A in the direction normal to BC is zero.

 


Option 1)

\frac{Q^{2}}{(4\pi \varepsilon _{0}a^{2})}\;

Option 2)

\; \; \frac{-Q^{2}}{(4\pi \varepsilon _{0}a^{2})}\;

Option 3)

\; Zero\;

Option 4)

\; \frac{Q^{2}}{(2\pi \varepsilon _{0}a^{2})}

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Aadil

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