Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Can someone help me with this, Two moles of helium gas is mixed with three moles of hydrogen molecules (taken to be rigid).What is the molar specific heat of mixture at constant volume ? (R=8.3 J/mol K)

Two moles of helium gas is mixed with three moles of hydrogen molecules (taken to be rigid).What is the molar specific heat of mixture at constant volume ? (R=8.3 J/mol K)

  • Option 1)

    15.7J/mol K

  • Option 2)

    17.4J/molK

  • Option 3)

    19.7J/molK

  • Option 4)

    21.6J/molK

 

Answers (1)

best_answer

 

Specific heat of gas at constant volume -

C_{v}= \frac{fR}{2}

- wherein

f = degree of freedom

R= Universal gas constant

 

 

C_{v} mix =\frac{n_{1}C_{v_{1}}+n_{2}C_{v_{2}}}{n_{1}+n_{2}}

=\frac{2\times\frac{3}{2}R+3\times\frac{5}{2}R}{2+3}

=\frac{3R+15\frac{R}{2}}{5}

=\left ( \frac{21}{10} \right )^{R}=\frac{21}{10}\times8.314

=17.4J/molK


Option 1)

15.7J/mol K

Option 2)

17.4J/molK

Option 3)

19.7J/molK

Option 4)

21.6J/molK

Posted by

solutionqc

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main Result 2024 Live: JEE Mains session 2 results at jeemain.nta.ac.in soon; rank predictor
anam-khan

JEE Main 2024 session 2 final answer key out at jeemain.nta.ac.in; steps to check probable scores
anam-khan

JEE Main Result 2024 Live: Download session 2 final answer key at jeemain.nta.ac.in; rank predictor, cutoff

Latest Question