When SnO2 is treated with NaOH, the negatively charged colloid consists of:

  • Option 1)

    S_{n}O_{2}:S_{n}O_{3}^{2-}

  • Option 2)

    S_{n}O_{2}:S_{n}^{4-}

  • Option 3)

    S_{n}O_{2}:OH^{-}

  • Option 4)

    S_{n}O_{2}:S_{n}^{2-}

 

Answers (1)

As we learned in concept

Preparation of Colloids -

Chemical Method

- wherein

Colloidal dispersion can be prepared by chemical reaction leading to formation of molecules by double decomposition, oxidation, reduction or hydrolysis.

AS_{2}O_{3}+3H_{2}S \overset{Double Decomposition}{\rightarrow} AS_{2}S_{3}+3H_{2}O

SO_{2}+2H_{2S}\overset{Oxidation}{\rightarrow}3S(sol)+2H_{2}O

 

 

The reaction occurs as follows:

S_nO_2+ 2NaOH\rightarrow Na_2S_nO_3+H_2O

Na_2S_nO_\rightarrow 2Na^{+} + S_nO_3^{2-}

So,negatively charged colloid consists of S_nO_2\: \: \: and\: \: S_nO_3^{2-}


Option 1)

S_{n}O_{2}:S_{n}O_{3}^{2-}

Correct option

Option 2)

S_{n}O_{2}:S_{n}^{4-}

Incorrect option

Option 3)

S_{n}O_{2}:OH^{-}

Incorrect option

Option 4)

S_{n}O_{2}:S_{n}^{2-}

Incorrect option

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