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  • Can someone help me with this, - Work Energy and Power - JEE Main

A force   \vec{F}= \left ( 5\hat{i} +3\hat{j}+2\hat{k}\right )N    is applied over a particle which displaces it from its origin to the point \vec{r}= \left ( 2\hat{i} -\hat{j}\right )m      The work done on the particle in joule is

Option 1)

-7

 Option 2)

+7
Option 3)

+10

 Option 4)

+13

Answers (2)

best_answer

\vec{F}=(5\widehat{i}+3\widehat{j}+2\widehat{k})N

\Delta\vec{R}=(2\widehat{i}-\widehat{j})m

Work done =\vec{F}.\Delta\vec{r}

    =(5\widehat{i}+3\widehat{j}+2\widehat{k}).()2\widehat{i}-\widehat{j})=7J

Correct asnswer is 2


Option 1)

-7

This is an incorrect option.

Option 2)

+7

This is the correct option.

Option 3)

+10

This is an incorrect option.

Option 4)

+13

This is an incorrect option.

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