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  • Carnot Cycle Efficiency An ideal heat engine operates on a Carnot cycle between a hot reservoir at <img alt="800 \mathrm{~K}" src="https://entrancecorner.oncodecogs.com/g

Carnot Cycle Efficiency

An ideal heat engine operates on a Carnot cycle between a hot reservoir at 800 \mathrm{~K} and a cold reservoir at 300 \mathrm{~K}. Calculate the efficiency of the engine.
 

Option: 1

0.625 \mathrm{k}

 


Option: 2

1.70 \mathrm{k}
 


Option: 3

5.20 \mathrm{k}
 


Option: 4

20.265 \mathrm{k}


Answers (1)

best_answer

Given data:

\mathrm{ T_h=800 \mathrm{~K} }

\mathrm{ T_c=300 \mathrm{~K}}

The efficiency of a Carnot engine is given by:

\mathrm{ \text { Efficiency }=1-\frac{T_c}{T_h} }

Plugging in the values:

\mathrm{ \text { Efficiency } = 1 -\frac{300 K }{800 K} }

\mathrm{\text{Efficiency=0.625}}

Therefore, the correct option is 1

Posted by

Irshad Anwar

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