5.325g sample of Methyl Benzoate, a compound used in the manufacturing of perfumes, is found to contain 3.758g of Carbon, 0.316g of Hydrogen and 1.251g of Oxygen. What is the empirical formula of the compound?

 Your Option is correct !!

A.

C4H4O

B.

C2H4O

C.

C2H2O

D.

C4H3O

Answers (1)

Empirical formula -

An Empirical formula represents the simplest whole-number ratio of various atoms present in a compound.

- wherein

for glucose, empirical formula is CH2O

 

Element % Mole ratio Simpleest mole ratio
C \frac{3.758\times 100}{5.325} = 70.57 \frac{70.57}{12} = 5.88 \frac{5.88}{1.47} = 4
H \frac{0.316\times 100}{5.325} = 5.93 \frac{5.93}{1} = 5.93 \frac{5.93}{1.47} = 4
O \frac{1.251\times 100}{5.325} = 23.50 \frac{23.50}{16} = 1.47 \frac{1.47}{1.47} = 1

So, Empirical formula is C4H4O

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