The hardness (in ppm) of a water sample containing 10^{-3}M \ CaSO_{4} is :

(molar mass of CaSO_{4}=136\ g mol^{-1}

 

Answers (1)

Moles of $\mathrm{CaSO}_{4}=10^{-3} \mathrm{moles}$
Mass of water =1000 \mathrm{g}$
DOH (in terms of \mathrm{CaCO}_{3}$  ) =\left(10^{-3} \times 100\right) / 1000 \times 10^{6}=100 \mathrm{ppm}$

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