Chlorine reacts with hot and concentrated NaOH and produces compounds (X) and (Y). Compound (X) gives white precipitate with silver nitrate solution. The average bond order between Cl and O atoms in (Y) is:
Option: 1 1.66
Option: 2 2.66
Option: 33.66
Option: 4 4.66
 

Answers (1)

As we have learnt,

Chlorine disproportionates in the presence of hot and concentrated NaOH to form chloride ions and chlorate ions 

\mathrm{Cl_{2}\: +\: 6NaOH(hot\: and\: conc.)\: \rightarrow \: NaClO_{3}\: +\: 5NaCl\: +\: 3H_{2}O}
                                                                                 Y                    X

\mathrm{NaCl\: +\: AgNO_{3}\: \rightarrow \: AgCl(s)\: +\: NaNO_{3}(aq)}
                                          white(ppt)

The structure of the Chlorate ion (ClO_3^-) is given below:

The average bond order is given as:

B.O = \frac{5}{3} = 1.66

Hence, the option number (1) is correct.

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