Chloro compound of Vanadium has only spin magnetic moment of 1.73 BM. This Vanadium chloride has the formula:
(Atomic number of V=23)
VCl2
VCl4
VCl3
VCl5
As we have learnt,
Magnetic Quantum Number (m) - It gives information about the spatial orientation of the orbital with respect to a standard set of the coordinate axis.
The value of the magnetic moment is 1.73 BM
where n is the number of unpaired electrons
After calculation n = 1
To obtain one unpaired electron V should be a tetra-positive ion and the formula of its chloride should be VCl4
Therefore, Option(2) is correct.
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