Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Choose the correct answer: Statement I:  is self-Indicator and <img alt="K_{2}Cr_{2}O_{7}" sr

Choose the correct answer:

Statement I: KMnO_{4} is self-Indicator and K_{2}Cr_{2}O_{7} is not.

Statement II: K_{2}Cr_{2}O_{7} behaves as an oxidizing agent only in acidic medium

Option: 1

Both the statements are true and Statement II is not the correct reason for Statement I.


Option: 2

Both the statements are true and Statement II is the correct reason for Statement I.


Option: 3

Both the statements are false.


Option: 4

Statement II is true and statement I is false.


Answers (1)

best_answer

potassium dichomate behaves as an oxidizing agent only in acidic medium, therefore it cannot be used self-indicator, as its reduction product gets itself blocked in the visual detection at the end of reaction.

Posted by

Gunjita

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JoSAA round 2 cut-off 2025 out; BTech closing ranks for top engineering courses at IITs
anam-khan

Goa Engineering Admission 2025: 1,415 eligible for BE seats; merit list on June 27
anam-khan

CSAB NEUT counselling 2025 registration begins today for BTech admissions in NE states, UTs

Latest Question