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Choose the correct option :
 
Option: 1 True dip is not mathematically related to apparent dip.
 
Option: 2  True dip is less than apparent dip.
 
Option: 3 True dip is always greater than the apparent dip.
 
Option: 4 True dip is always equal to apparent dip.

Answers (1)

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\delta '\rightarrow Apparent\: \: angle\: \: of \, \, dip

\delta \rightarrow True \: \: angle \: \: of \: \: dip

\begin{gathered} \tan \delta =\frac{B_V}{B_{H}} \\ \end{gathered}

\begin{gathered} \tan \delta ^{\prime}=\frac{B_V}{B_{H} \cos \alpha} \\ \end{gathered}

\begin{gathered} \therefore As \quad \cos \alpha< 1 \quad(\alpha \neq 0) \\ \end{gathered}

\begin{gathered} \therefore \tan \delta ^{\prime}>\tan \delta \\ \end{gathered}

            \begin{gathered} \delta^{\prime}>\delta \end{gathered}

The correct answer is option (2)

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vishal kumar

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