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  • Complete combustion of 3 g of ethane gives molecules of water. The value of x is ________. (Round off to the Nearest Integer). [Use : NA = 6.023 x 1023

Complete combustion of 3 g of ethane gives x \times 10^{22} molecules of water. The value of x is ________. (Round off to the Nearest Integer). [Use : NA = 6.023 x 1023; Atomic masses in u : C : 12.0 ; O : 16.0 ; H : 1.0]
 

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Complete combustion of 3 g of ethane-

 3 g of ethane gives 0.3 mol of water.

1 mole =  6.023 x 1023 molecules 

So,  0.3 mole = 0.3 x 6.023 x 1023 molecules 

0.3 mole = 18.069 x 1022 molecules 

Hence, x = 18

Ans = 18

Posted by

Kuldeep Maurya

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